Binary Tree Preorder Traversal
Given the root
of a binary tree, return the inorder traversal of its nodes' values.
Example 1:

Input: root = [1,null,2,3] Output: [1,3,2]
Example 2:
Input: root = [] Output: []
Example 3:
Input: root = [1] Output: [1]
Constraints:
- The number of nodes in the tree is in the range
[0, 100]
. -100 <= Node.val <= 100
Solution With C++
class Solution {
public:
vector<int>d;
vector<int> inorderTraversal(TreeNode* root) {
if(root==NULL) return d;
d=inorderTraversal(root->left);
d.push_back(root->val);
d=inorderTraversal(root->right);
return d;
}
};
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